#1**+2 **

\({5x-2\over x+3} = 5 - {17 \over x+3}~\\ \qquad 5(x+3)=5x+15\\ LHS\\={5x-2\over x+3}\\={5(x+3)-15-2\over x+3}\\={5(x+3)-17\over x+3}\\= {5(x+3)\over x+3}-{17\over x+3}\\= 5-{17\over x+3}\ \)

This is not really what you were expected to do though.

You were expected to do algebraic division or synthetic division

**This is an example of what you were supposed to do :)**

Melody
Feb 12, 2018