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\({5x-2\over x+3} = 5 - {17 \over x+3}\)

Guest Feb 12, 2018
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\({5x-2\over x+3} = 5 - {17 \over x+3}~\\ \qquad 5(x+3)=5x+15\\ LHS\\={5x-2\over x+3}\\={5(x+3)-15-2\over x+3}\\={5(x+3)-17\over x+3}\\= {5(x+3)\over x+3}-{17\over x+3}\\= 5-{17\over x+3}\ \)

 

This is not really what you were expected to do though.

You were expected to do algebraic division or synthetic division

 

This is an example of what you were supposed to do :)

 

https://www.youtube.com/watch?v=H94ma2ofGuc

Melody  Feb 12, 2018

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