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# What The Code Puzzle - 18 June A man desired to get into his work building, however he had forgotten his code. However, he did recollect fiv

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What The Code Puzzle - 18 June A man desired to get into his work building, however he had forgotten his code. However, he did recollect five pieces of information * Fifth number + Third number = 14 * The fourth number is one more than the second number. * The first number is one less than twice the second number. * The second number and the third number equals 10. * The sum of all five numbers is 30. What is the code ? For Solution : Click Here

Aug 15, 2015

#4
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Let a, b, c, d and e be the digits in that order...so,we have the following system:

c + e = 14

d - b  = 1

2b - a = 1

b + c = 10

a + b + c + d + e  = 30    (5)

Notice that

c + e = 14

c + b = 10      subtracting the second equation from the first, we have

e - b = 4    → e = b + 4

And c = 10 - b

And d = 1 + b

And a = 2b - 1

And substituting all these into equation (5), we have

(2b - 1) + b + (10 - b) + (1 + b) + (b + 4) = 30    simplify

4b + 14 = 30     subtract 14 from each side

4b = 16  → b = 4

Then

c = 10 - 4 = 6

d = 1 + 4 = 5

e = 4 + 4  = 8

a = 2(4) - 1 = 7

And the code is:

abcde = 74658

Just as Anonymous found!!!!!   Aug 15, 2015

#1
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Was that supposed to be a hyperlink to the answer Maia?

Aug 15, 2015
#2
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Yeah but It does not work bcz I pasted the question

Aug 15, 2015
#4
+10

Let a, b, c, d and e be the digits in that order...so,we have the following system:

c + e = 14

d - b  = 1

2b - a = 1

b + c = 10

a + b + c + d + e  = 30    (5)

Notice that

c + e = 14

c + b = 10      subtracting the second equation from the first, we have

e - b = 4    → e = b + 4

And c = 10 - b

And d = 1 + b

And a = 2b - 1

And substituting all these into equation (5), we have

(2b - 1) + b + (10 - b) + (1 + b) + (b + 4) = 30    simplify

4b + 14 = 30     subtract 14 from each side

4b = 16  → b = 4

Then

c = 10 - 4 = 6

d = 1 + 4 = 5

e = 4 + 4  = 8

a = 2(4) - 1 = 7

And the code is:

abcde = 74658

Just as Anonymous found!!!!!   CPhill Aug 15, 2015