That's pretty simple, rosala....think of it like this....we're just taking something out of the absolute value "as is" and solving one equation. And then, we're making it "negative" and solving a second equation. If you can solve the first equation, the second one isn't any tougher....!!!!
The first step is to create two equations:
1) 4x + 3 = 5x + 7
2) -(4x + 3) = 5x + 7 --> -4x - 3 = 5x + 7.
Note, rosala, that if we have lNl = 3
Then N might be +3 or -3
So...if we have
[4x + 3l = 5x + 7
Then we might have a "positive" (4x +3) or a "negative" (4x + 3)
Does that make sense??
Here is the graph, https://www.desmos.com/calculator/j9gxp4g9wc
Imagine if you continued to extend the lines. We would have two lines. One would have a positive slope and the other, a negative slope. The y-intercepts would be 3 and -3, and the slopes 4 and -4.
y = 4x +3
y = -4x - 3
That's pretty simple, rosala....think of it like this....we're just taking something out of the absolute value "as is" and solving one equation. And then, we're making it "negative" and solving a second equation. If you can solve the first equation, the second one isn't any tougher....!!!!