its good to be back
3 / 2 5/8
first, lets put these fractions improper3*8/8=24/8
2*8=16+5=21/8
now its: $${\frac{{\frac{{\frac{{\mathtt{24}}}{{\mathtt{8}}}}}{{\mathtt{21}}}}}{{\mathtt{8}}}}$$
now, lets do the recipicult to the numerator and denomenator of the second fraction, in this case, 21/8
now we converted this division situation to a multiplication situation
$${\frac{{\frac{{\mathtt{24}}}{{\mathtt{8}}}}{\mathtt{\,\times\,}}{\mathtt{8}}}{{\mathtt{21}}}}$$
cross cancel both 8s on both fractions cuz they cross
which leads to this after cross canceling:
$${\frac{{\frac{{\mathtt{24}}}{{\mathtt{1}}}}{\mathtt{\,\times\,}}{\mathtt{1}}}{{\mathtt{21}}}}$$
now multiply, which should equal:
$${\frac{{\mathtt{24}}}{{\mathtt{21}}}}$$=1 3/21=1 1/7
overall, 3 divided by 2 5/8=1 1/7