whats a^-3*(b^4)-2
b^5*a^4
??????
whats a^-3*(b^4)-2 / b^5*a^4
Simplify the following:
(b^4/a^3-2)/(b^5 a^4)
Put each term in b^4/a^3-2 over the common denominator a^3: b^4/a^3-2 = b^4/a^3-(2 a^3)/a^3:
(b^4/a^3-(2 a^3)/a^3)/(b^5 a^4)
b^4/a^3-(2 a^3)/a^3 = (b^4-2 a^3)/a^3:
((b^4-2 a^3)/a^3)/(b^5 a^4)
Combine powers. (b^4-2 a^3)/(b^5 a^4 a^3) = ((b^4-2 a^3) a^(-3-4))/b^5:
(a^-3-4 (b^4-2 a^3))/b^5
-3-4 = -7:
Answer: | (a^-7 (b^4-2 a^3))/b^5
+118667 whats a^-3*(b^4)-2
b^5*a^4
\(\frac{a^{-3}*(b^4)^{-2}}{b^5*a^4}\\ =\frac{a^{-3}*b^{-8}}{b^5*a^4}\\\)
Now the way you deal with negativie indices is:
Is something is raised to a negaive indice then swap it to the other side of the fraction line and chang the negative power to a positive power.
Anything NOT raised to a negative power stays right where it started!
(don't confuse negative coefficients with negative powers - but there are no negative coefficients here anyway)
\(=\frac{a^{-3}*b^{-8}}{b^5*a^4}\\ =\frac{1}{b^5*a^4*a^{+3}*b^{+8}}\\ \mbox{Since there was nothing left on the top I put a one there}\\ =\frac{1}{b^5*b^8*a^4*a^3}\\ =\frac{1}{b^{13}a^7}\\\)
