+980 Whats the area of a rhombus thats angles are 120, 120, 60, and 60 who's sides all equal six.
+1094 The great thing about this problem is that the angles are 120, 120, 60, 60, which means that you can divide this rhombus into two equilateral triangles.
Using the area formula for euqilateral triangles ,\(\frac{\sqrt{3}}{4} a^{2}\), we see that the areas of each triangle is \(9\sqrt 3\). Multiply that by 2, and you get your answer: \(\boxed{18\sqrt 3}\)
+680 You could also use an alternate solution by using the diagonal formula for a rhombus area. That formula is multiply the diagonals together and divide by 2.
