Whats the linear measure of an arc whose central angle is 80* on a circle having a radius of 18 meters?
I really liked this question Rose.
I'd do it CPhill's way.
the whole circumference it 2pi*r
But you only have 80degrees out of a total of 360 degrees in the whole cirlce.
so the answer must be given by
$$arc\;length= \frac{80}{360}\times 2\pi r => \frac{80}{360}\times 2\pi\times 18$$ etc
Good question. Do you know about the formula? Or may you give a hint?
The total circumference is 2*pi*18 = 36pi
Note that we only want (80/360)ths = (2/9)ths of this.
So, (80/360)*36pi = (2/9)*36pi = 8pi
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The above is a "corrected" answer!!...Mainly because I forgot what I was doing!!!
I really liked this question Rose.
I'd do it CPhill's way.
the whole circumference it 2pi*r
But you only have 80degrees out of a total of 360 degrees in the whole cirlce.
so the answer must be given by
$$arc\;length= \frac{80}{360}\times 2\pi r => \frac{80}{360}\times 2\pi\times 18$$ etc