#1**0 **

with x =0, you know y=100

so only the bottom two have a point 0,100

then it is trial and error.

plug in 2 for x and 0 for y,

if that works then it is the bottom left one.

if not then it is the other one,

you could check the bottom right with -2,0 or 5,0 as well

but 5,0 is an assumption since the 5 isnt labled.

so i would do this

0=(2)^4 - 6(2)^3 - 11(2)^2 +60(2)+100

Guest Mar 1, 2018

#2**+1 **

If x = 0...then y = 100

Thus....one of the two bottom graphs must be correct

Notice in the bottom left graph that 2 appears to be a root.....testing this in the polynomial should produce a result of 0

y=2^4−6(2)^3−11(2)^2+60(2)+100 = 144

So...the bottom right graph is correct

CPhill
Mar 1, 2018