+130085 √[ 2x - 1 ] - x + 2 = 0 rearrange as
√ [2x - 1 ] = x - 2 square both sides
2x - 1 = ( x-2)^2
2x - 1 = ( x - 2) ( x - 2)
2x - 1 = x^2 - 4x + 4 subtract 2x from both sides, add 1 to both sides
x^2 - 4x - 2x + 4 + 1 = 0
x^2 - 6x + 5 = 0 factor
(x - 5) ( x - 1) = 0
Setting each factor to 0 and solving for x we get the possible solutions of
x = 5 or x = 1
Note that x = 5 solves the original equation but x = 1 doesn't
So ... the last answer is correct
