+0

# who can help me ...

+3
393
4
+1832

Aug 3, 2014

#1
+4473
+18

17. The amplitude is 2. Each wavelength is 6. When x = 0, y = 1.

The only one that matches x = 0, y = 1 is e, f(x) = 1 + sin x since all the others don't satisfy this condition.

19. f(x) = 2x^2 + 3

f(x+h) = 2(x+h)^2 + 3 = 2x^2 + 4xh + 2h^2 + 3 -->

2x^2 + 4xh + 2h^2 + 3 - (2x^2 + 3) / h -->

4xh + 2h^2 / h -->

b, 4x + 2h.

Aug 3, 2014

#1
+4473
+18

17. The amplitude is 2. Each wavelength is 6. When x = 0, y = 1.

The only one that matches x = 0, y = 1 is e, f(x) = 1 + sin x since all the others don't satisfy this condition.

19. f(x) = 2x^2 + 3

f(x+h) = 2(x+h)^2 + 3 = 2x^2 + 4xh + 2h^2 + 3 -->

2x^2 + 4xh + 2h^2 + 3 - (2x^2 + 3) / h -->

4xh + 2h^2 / h -->

b, 4x + 2h.

AzizHusain Aug 3, 2014
#2
+1832
+3

In question 17

what do I benifit from the amplitude and the wavelength !! ?

Aug 3, 2014
#3
+121078
+13

You don't really need to worry about the amplitude and wavelength (period)..the "1" out in front of 1 + sinx tells us that it's a sine graph shifted up 1 unit and none of the graph will lie below the x axis.......all the other graphs (answers) will have pieces that lie below the x axis...

Aug 3, 2014
#4
+1832
+3

thanx for all

Aug 3, 2014