https://drive.google.com/file/d/1odNMgKHGyDdQpiHJkrn8Ut_HGEAG-wAP/view?usp=sharing
Its a proof that apparently seems obvious but no one gets right for some reason.
+68 | NORT is a parallelogram | Given |
| NO=OR=NT=TR | Given |
| NORT is a rhombus | definition of rhombus |
| OT bisects NR | in a parallelogram, diagonals bisect |
| NH=HR | definition of segment bisect |
| OH=OH | reflexive property of equality |
| triangle NOH=triangleROH | SSS congruency theorem |
| OHN=OHR | CPCTC |
| OHR+OHN=180 | linear pair |
| OHN+OHN=180 | substitution |
| 2OHN=180 | simplify |
| OHN=90, OHR=90 | division property of equality |
| OT perpendicular to NR | definition of perpendicular |
I changed your chart a bit to make it more specific. I myself am a geometry student as well so if anyone sees anything that's wrong, don't be afraid to tell me!
