Its a proof that apparently seems obvious but no one gets right for some reason.
|NORT is a parallelogram||Given|
|NORT is a rhombus||definition of rhombus|
|OT bisects NR||in a parallelogram, diagonals bisect|
|NH=HR||definition of segment bisect|
|OH=OH||reflexive property of equality|
|triangle NOH=triangleROH||SSS congruency theorem|
|OHN=90, OHR=90||division property of equality|
|OT perpendicular to NR||definition of perpendicular|
I changed your chart a bit to make it more specific. I myself am a geometry student as well so if anyone sees anything that's wrong, don't be afraid to tell me!