+308 a^x + b^y = c^z
Where A, B, C, x, y and z are positive integers and x, y and z are all greater than 2, then A, B and C must have a common prime factor. The challenge is to either solve that conjecture or come up with a counter-example.
(the Beal Conjecture I believe it's called)
+308 No I mean Beal will give you 1 mil dollars if you solve it correctly. Not me you idiot.
+308 You don't know who tf Beal is do you?
He is a Millionaire dude. He has the money.
-156 I'm just saying Beal>Beal you didn't know there were 2 beals, you fool
