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# Why are these two functions graphed differently?

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Here are my two functions:

\(y_1 = {2x + 6}\) and \(y_{2} = {-x + 9}\).

For \({y_1}\), the y-intercept is \({6}\) like it should be for \(y = {mx + b}\).

However, for \({y_2}\), the value \({9}\) is used as a translation and not for the y-intercept. Aren't they both in \(y = {mx + b}\)?

I'm just very curious as to why these two functions are graphed differently!

Oct 22, 2018

#1
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They are not graphed differently, it is just 2 different ways to think of the same thing.

y=2x+6   is  y=2x with a upwards translation of +6 giving the line a y intercept of 6

y=-x+9   is   y=-x with an upwards translation of +9  giving the line a y intercept of 9

It is a good question because it demonstrates that you are thinking about what is happening Oct 22, 2018

#1
+2

They are not graphed differently, it is just 2 different ways to think of the same thing.

y=2x+6   is  y=2x with a upwards translation of +6 giving the line a y intercept of 6

y=-x+9   is   y=-x with an upwards translation of +9  giving the line a y intercept of 9

It is a good question because it demonstrates that you are thinking about what is happening Melody Oct 22, 2018
#2
+1   CPhill  Oct 22, 2018
#3
+1

Thanks Chris :)

Melody  Oct 22, 2018