why is $${\left(-{\mathtt{6}}\right)}^{-{\mathtt{1}}}$$ a negative answer and $${{\mathtt{\,-\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right)}^{-{\mathtt{2}}}$$ positive?
Remember that : a-n = 1/an
So (-6)-1 = 1/-6 = -(1/6)
And (-1/2)-2 = 1 / (-1/2)2 = 1/ [ (-1/2) * (-1/2)] = 1 / (1/4) = 4
$$\\(-6)^{-1}=\frac{1}{(-6)^1}=\frac{1}{-6}=-\frac{1}{6}\\\\\\
-\left(\frac{1}{2}\right)^{-2}
=-\left(\frac{2}{1}\right)^{+2}
=-\frac{2^2}{1^2}
=-4$$
So they are both negative. Does that help or do you want to quiz me about it?
Added later: Oh i will do the heading one too
$$\left(\frac{-1}{2}\right)^{-2}
=\left(\frac{2}{-1}\right)^{+2}
=\frac{2^2}{(-1)^2}
=\frac{2*2}{-1*-1}
=\frac{4}{1}
=4$$