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why is y squared plus x squared equals 41 a circle?

 Mar 30, 2015

Best Answer 

 #1
avatar+128707 
+10

We can show, using trigonometry, that any point  (x, y) on a circle of radius R can be expressed as

(Rcosθ, Rsinθ)   where  θ is just some angle

So

x^2  + y^2 =  R^2cos^2θ + R^2sin^2θ  = R^2(cos^2θ  + sin^2θ)

But..... (cos^2θ  + sin^2θ)  = 1  ......so we have

x ^2 + y^2   = R^2

And if we let R = √41, then R^2  = 41   and we have

x^2 + y^2  = 41

And there you go......!!!

 

   

 Mar 30, 2015
 #1
avatar+128707 
+10
Best Answer

We can show, using trigonometry, that any point  (x, y) on a circle of radius R can be expressed as

(Rcosθ, Rsinθ)   where  θ is just some angle

So

x^2  + y^2 =  R^2cos^2θ + R^2sin^2θ  = R^2(cos^2θ  + sin^2θ)

But..... (cos^2θ  + sin^2θ)  = 1  ......so we have

x ^2 + y^2   = R^2

And if we let R = √41, then R^2  = 41   and we have

x^2 + y^2  = 41

And there you go......!!!

 

   

CPhill Mar 30, 2015
 #2
avatar+118613 
+5

On a more basic level

the formula of any circle in the x,y plane is     

 

   $${\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{h}}\right)}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\left({\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{k}}\right)}^{{\mathtt{2}}} = {{\mathtt{r}}}^{{\mathtt{2}}}$$

 

where (h,k) is t he centre and r is the radius :)

 Mar 31, 2015

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