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# Why this integral no work?

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$$\int_{0}^{5} h(x)dx = 0$$ That is what I got after trying to figure out the area of a square using an integral. h(x) = 5 creating a square... the area is 25 but why this integral no work? A line is a curve too!!!

Guest Jun 26, 2017
#1
+520
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First, the integral of 5 with respect to x is 5x

Next, you evaluate this 5x at x=5 and at x=0

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edited by Badinage  Jun 26, 2017
#2
+92806
+2

$$\int_{0}^{5} h(x)dx = 0$$

That is what I got after trying to figure out the area of a square using an integral. h(x) = 5 creating a square... the area is 25 but why this integral no work? A line is a curve too!!!

h(x)=5

$$A=\int_{0}^{5} h(x)dx \\ =\int_{0}^{5} \;5\:dx \\ =\left[5x\right]_0^5\\ =25-0\\ =25 units^2$$

My integral works just fine.

Melody  Jun 26, 2017