Will an 18 foot pole fit into a space 15'7" long by 6'5" high by 7'5" wide?

Guest May 10, 2015

#1**+5 **

15 ft 7 in = about 15.583 ft

6 ft 5 in = about 6.416 ft

7 ft 5 in = about 7.416 ft

To see if the pole will fit.......we need to find the length of the diagonal of the cube by squaring each one of the above, adding the results.....then taking the square root of the last calculation.....thusly:

√[ 15.583^2 + 6.416^2 + 7.416^2 ] = √338.992001 = about 18.411 ft ..... yep...it will fit !!!

Note.....this is analogous to the Pythagorean Theorem....only it's in 3-D !!!!

CPhill May 10, 2015

#1**+5 **

Best Answer

15 ft 7 in = about 15.583 ft

6 ft 5 in = about 6.416 ft

7 ft 5 in = about 7.416 ft

To see if the pole will fit.......we need to find the length of the diagonal of the cube by squaring each one of the above, adding the results.....then taking the square root of the last calculation.....thusly:

√[ 15.583^2 + 6.416^2 + 7.416^2 ] = √338.992001 = about 18.411 ft ..... yep...it will fit !!!

Note.....this is analogous to the Pythagorean Theorem....only it's in 3-D !!!!

CPhill May 10, 2015