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# Word problem Help

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Mr. Williams bought a car worth $120,493. (Not Really.) The car depreciates at a rate 31.9% annually. What is the car worth after 4 years? 9 years? Apr 20, 2015 ### Best Answer #5 +981 +5 Thanks :) Apr 20, 2015 ### 5+0 Answers #1 +60 +5 31.9% = 0.319, so all you have to do is solve the equation 120,493 - (120,493 * 0.319^n), where n stands for the number of years. So... 120,493 - (120,493 * 0.319^4) = 119245.26 , so$119245.26 on the 4th year

120,493 - (120,493 * 0.319^9) = 120488.88 , so \$120488.88 on the 9th year

(The answers where rounded to the nearest hundreth)

Apr 20, 2015
#2
+5

So this is an exponential decay problem which the formula is y=ab^x where x would be < 1 so this equation would be y=120,493 • .681^x. You would find get the a value by the  the initial value and the b value by subtracting 100 the percent that they give you.  So after 4 years you would have 17648.0765, after 9 years 3795.64708.

Apr 20, 2015
#3
+981
+5

The depreciation of the car can be written as

Future value(FV) = Present Value(P)*(1-rate(i))^number of years(n), or

$$FV=P(1-i)^n$$

so for 4 years . . .

$$FV=120493\times(1-0.319)^4=25914.94$$

And for 9 years . . .

$$FV=120493\times(1-0.319)^9=3795.65$$

.
Apr 20, 2015
#4
+99352
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Zectico, if you think about the answers that you got you will see that they simpley do not makes sense.

e.g.   The car is worth more after 9 years than it was after 4.

Anon,  you started off good but then I don't know what you did :/

(I think i will give you latter 2  points for your efforts  :))

Apr 20, 2015
#5
+981
+5