+0  
 
0
489
1
avatar+1678 

Bob has 20 dollars. Bill has y dollars.
They decided to go to the movies. They only paid for their own tickets. Bob spent 2/5 of his money and Bill spent 4/15 of his money.
If the tickets were the same amount of money, how much money does Bill have?

 Feb 25, 2021
 #1
avatar+25 
+2

First, you have to find how much each ticket costs. Bob has 20 dollars, and he spends 2/5 of it on the movie ticket. To find this, you can simply do 20*(2/5). You can also see that 1/5 of 20 dollars is 4 because 20/5=4. He used 2/5 which is double of 1/5 which means the ticket is 2*4=8. Using both methods, your answer will be, the movie ticket is 8 dollars. 

Since the problem says that the tickets were the same amount of money, you can make the equation: 8=y*(4/15). The 8 stands for the price of the movie ticket, the y stands for how much money Bill has, and the 4/15 stands for the fraction of Bill's money spent on the movie ticket. As shown above, y*(4/15) will tell you how much 4/15 of y is. 

 

Solving for y, you get 30. In conclusion, Bill has 30 dollars.

 

This is my FIRST every response to a question so hopefully this helps :)

 

(I do all my calculations on paper so you should probably solve the equations yourself to make sure I didn't make any silly mistakes.)

 Feb 25, 2021

5 Online Users

avatar
avatar
avatar