Bob has 3/4 as much money as Dan. Dan received another $15. As a result, Bob had 6/11 as much money as Dan. How much did Dan have at first?

Guest Jun 21, 2021

#1**+2 **

B = (3/4)D

After Dan received $15 he has D + 15

So

B / ( D + 15) = 6/11

(3/4)D / ( D + 15) = 6 /11 cross-multiply

11 * ( 3/4)D = 6 (D + 15)

(33/4)D = 6D + 90

(33/4)D - 6D = 90

(33/4)D - (24/4)D = 90

(9/4)D = 90

D = (4/9) (90) = $40 = what Dan started with

CPhill Jun 21, 2021

#2**+2 **

B = 3/4 D

Then add 15 to D

B = 6/11(D+15) Sub in the red equation

3/4D = 6/11D + 90/11

(33-24)/44 D = 90/11

D = 44/9 * 90/11 = 40 Dollars (as CHris already showed !)

ElectricPavlov Jun 21, 2021