A standard set of dominoes contain 28 tiles, with each tile having two sides of dots from 0 to 6. Of these tiles, 7 have the same number of dots on each side. If four players each randomly choose a tile, without replacement, what is the probability, that each chooses a tile with the same number of dots on each side?

BadMathPerson12
Apr 19, 2017

#1**+2 **

The first person has a 7/28 = 1/4 probability of choosing such a domino

The second = 6/27 = 2/9

The third = 5/26

And the fourth = 4/25

Multiplying these together, we have

(1/4) (2/9) ( 5/26) (4/25) =

(1/4) (2/9) (5/25) (4/26) =

(1/4) (2/9) (1/5)(2/13) =

4 / 2340 =

1 / 585 ≈ 0.17%

CPhill
Apr 19, 2017