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A standard set of dominoes contain 28 tiles, with each tile having two sides of dots from 0 to 6. Of these tiles, 7 have the same number of dots on each side. If four players each randomly choose a tile, without replacement, what is the probability, that each chooses a tile with the same number of dots on each side? 

BadMathPerson12  Apr 19, 2017
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The first person has a 7/28  = 1/4 probability of choosing such  a domino

The second = 6/27 =  2/9

The third = 5/26

And the fourth  = 4/25

 

Multiplying these together, we have

 

(1/4) (2/9) ( 5/26) (4/25) =

(1/4) (2/9) (5/25) (4/26) =

(1/4) (2/9) (1/5)(2/13)  =

 

4 / 2340   =

 

1 / 585  ≈  0.17%

 

 

cool cool cool

CPhill  Apr 19, 2017
edited by CPhill  Apr 19, 2017

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