+0

# word problem

0
54
2

Tickets to the fair cost \$4 for children and \$11 for adults. On Wednesday 177 people enter thefair and they collected \$1380. What number of children and what number of adults attended?

Sep 29, 2020

#1
+1

To solve this, you can use quadratics. x + y = 177 and 4x + 11y = 1380 are the equations to solve for x and y. 177 is the total amount of people who entered the fair, and 1380 is the total money earned. x is the amount of children entered, while y is the amount of adults entered. If we were to do 4(x + y = 177), the equation would become 4x + 4y = 708. Then, we minus the 2 equations together, eliminating the x so we can solve for y. So, the final equation is 7y = 672, meaning y = 96. If we bring this into the first equation, x + y = 177, we can find that x = 81. So this means the answer is 81 children and 96 adults.

Sep 29, 2020
#2
+111144
0

Thanks for answering. But it is very hard to read and comprehend when it is all squashed up like that.

Melody  Sep 30, 2020