the school is selling tickets to the annual dance competition on the first day of ticket sales the school sold 2 adult tickets and 9 student tickets for a total of $68 the school took in $76 on the second day by selling 10 adult tickets and 1 student ticket what is the price each of one adult ticket and one student ticket answer
+36916 2a + 9s = 68
10a + 1s = 76 This is all given.... Now multiply the top equation by - 5
-10a -45s = -340 now when you add the two bottom equations 'a' is eliminated
- 44s = -264 s= 6 now you can sub this into one of the equations to solve for 'a' to finish the answer.........
+2666 \(a\) = adult tickets sold
\(s\) = student tickets sold
\(2a+9s=68\)
\(10a+s=76\)
Solve for the system, and you find that a student ticket costs \(\color{brown}\boxed{6}\), and you can find what an adult ticket costs by subsituting.
