+73 Write a mathematical proof of the algebraic equivalence of (pq)r and (qr)p.
+4609 We use the associative property of multiplication, which is: x*(y*z)=(x*z)*y.
So, here we have: (pq)r and (qr)p.
It doesn't matter where the brackets are around the numbers, it is still going to yield the same value.
Here's an example: 2,3,4
We have (2*3)*4=(3*4)*2=6*4=12*2
24=24, yay!
