write a sequence of odd natural numbers starting from 1. What is the 2023th digit?

Your sequence would look something like this:

 

1, 3, 5, 7, ...

 

Notice how you keep adding two. And notice how the number of times you add two is one less than the term number. 

 

For example, 3 = 1 + 2

(We added 2 only once to calculate the second term) Vice versa for all. 

 

The equation is therefore:

1 + 2(n - 1)

 

Substitute 2023 for n. 

 

1 + 2(2023 - 1)

= 1 + 2(2022)

= 1 + 4044

= 4045

 

Therefore, 2023rd number is 4045. 

 

 

1, 3, 5, 7, 9, 11,........................1281, 1283, 1285, 1287, 1289.

 

The 2023th digit is: 2 of 1289

 

There are: 5 digits from 1 to 9

There are:90 digits from 11 to 99

There are:1350 digits from 101 to 999

There are:576 digits from 1001 to 1287

 

5 + 90 + 1350 + 576 ==2021 digits

So, the 2023th digit will be: 2 of 1289