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Write an exponential equation in the form y = abx whose graph passes through points (−3, 24) and (−2, 12).
y = −3(24)x
y = 0.5(3)x
y = 3x
y = 3(0.5)x
+130071 Write an exponential equation in the form y = ab^x whose graph passes through points (−3, 24) and (−2, 12).
We have this
24 = a(b)^(-3)
12 = a(b)^(-2) divide the second equation by the first
(1/2) = b
Sub this into the second equation
12 = a (1/2)^(-2)
12 = a (4)
3 = a
So...the equation is
y = 3 (1/2)^(x) = 3(0.5)^x
