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Write the following in scientific notation i.8600,     0,000025,    94513228,   4280000000, 193

 Jul 8, 2015

Best Answer 

 #1
avatar
+5

hi,

the first thing you should do when trying to covert is shift your decimal to the first significant digit form the left, in your case 0.000025 should become 2.5.

now the next part would be to count how far you moved your decimal either right or left to accomodate a bigger or smaller number respectively.

for 0.000025 you moved the decimal 5 spaces to the right to make your 2.5. this means that your exponent in scientific notation would be -5. so your final answer would be

$${\mathtt{2.5}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{5}}}$$

for a big number, like 94513228, you would move it to the left, and your exponent would be positive rather than negative, and you'd round numbers after your decimal because you know them.

so you'd move the decimal 7 spots to the left, and raise the 10 to a power of 7!

so 94513228 would become:

$${\mathtt{9.45}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{7}}}$$

hope this helps!

 Jul 8, 2015
 #1
avatar
+5
Best Answer

hi,

the first thing you should do when trying to covert is shift your decimal to the first significant digit form the left, in your case 0.000025 should become 2.5.

now the next part would be to count how far you moved your decimal either right or left to accomodate a bigger or smaller number respectively.

for 0.000025 you moved the decimal 5 spaces to the right to make your 2.5. this means that your exponent in scientific notation would be -5. so your final answer would be

$${\mathtt{2.5}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{5}}}$$

for a big number, like 94513228, you would move it to the left, and your exponent would be positive rather than negative, and you'd round numbers after your decimal because you know them.

so you'd move the decimal 7 spots to the left, and raise the 10 to a power of 7!

so 94513228 would become:

$${\mathtt{9.45}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{7}}}$$

hope this helps!

Guest Jul 8, 2015

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