Write x^2 + 6x - 7 in the form of (x + a)^2 + b

where a and b are integers

YEEEEEET Mar 8, 2018

#1**0 **

**Write x^2 + 6x - 7 in the form of (x + a)^2 + b where a and b are integers**

\(\begin{array}{|rcll|} \hline && (x+a)^2+b \\\\ &=& x^2+\underbrace{2a}_{=6}x + \underbrace{a^2 +b}_{=-7} \\\\ 2a = 6 && a^2+b =-7 \\ a = 3 && 3^2+b = -7 \\ && b =-7-9 \\ && b = -16 \\\\ && \mathbf{(x+3)^2-16} \\ \hline \end{array}\)

heureka Mar 8, 2018

#1**0 **

Best Answer

**Write x^2 + 6x - 7 in the form of (x + a)^2 + b where a and b are integers**

\(\begin{array}{|rcll|} \hline && (x+a)^2+b \\\\ &=& x^2+\underbrace{2a}_{=6}x + \underbrace{a^2 +b}_{=-7} \\\\ 2a = 6 && a^2+b =-7 \\ a = 3 && 3^2+b = -7 \\ && b =-7-9 \\ && b = -16 \\\\ && \mathbf{(x+3)^2-16} \\ \hline \end{array}\)

heureka Mar 8, 2018