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Write x^2 + 6x - 7 in the form of (x + a)^2 + b 

where a and b are integers

 Mar 8, 2018

Best Answer 

 #1
avatar+21242 
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Write x^2 + 6x - 7 in the form of (x + a)^2 + b
where a and b are integers

 

\(\begin{array}{|rcll|} \hline && (x+a)^2+b \\\\ &=& x^2+\underbrace{2a}_{=6}x + \underbrace{a^2 +b}_{=-7} \\\\ 2a = 6 && a^2+b =-7 \\ a = 3 && 3^2+b = -7 \\ && b =-7-9 \\ && b = -16 \\\\ && \mathbf{(x+3)^2-16} \\ \hline \end{array}\)

 

laugh

 Mar 8, 2018
edited by heureka  Mar 9, 2018
 #1
avatar+21242 
0
Best Answer

Write x^2 + 6x - 7 in the form of (x + a)^2 + b
where a and b are integers

 

\(\begin{array}{|rcll|} \hline && (x+a)^2+b \\\\ &=& x^2+\underbrace{2a}_{=6}x + \underbrace{a^2 +b}_{=-7} \\\\ 2a = 6 && a^2+b =-7 \\ a = 3 && 3^2+b = -7 \\ && b =-7-9 \\ && b = -16 \\\\ && \mathbf{(x+3)^2-16} \\ \hline \end{array}\)

 

laugh

heureka Mar 8, 2018
edited by heureka  Mar 9, 2018

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