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 Jun 18, 2014

Best Answer 

 #1
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First remember the basic equation of a circle (x-h)^2+(y-k)^2=r^2   where (h,k) is the center of the circle and r is the radius.  For this question it appears the center is at (3,-2) and the radius looks to be three so that would give us a standard form equation of (x-3)^2 +(y+2)^2=9.   

 Jun 18, 2014
 #1
avatar
+10
Best Answer

First remember the basic equation of a circle (x-h)^2+(y-k)^2=r^2   where (h,k) is the center of the circle and r is the radius.  For this question it appears the center is at (3,-2) and the radius looks to be three so that would give us a standard form equation of (x-3)^2 +(y+2)^2=9.   

Guest Jun 18, 2014

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