((x-2)/(2x)+(1)/(x+2))/((3)/(2)-(6)/(x^(2)+2x))
How would I solve this?
Please give step by step directions on how to solve
How would I solve this?
((x-2)/(2x)+(1)/(x+2))/((3)/(2)-(6)/(x^(2)+2x))
x−22x+1x+232−6x2+2x|x2+2x=x(x+2)=x−22x+1x+232−6x(x+2)=(x−2)(x+2)+1⋅2x2x(x+2)3x(x+2)−2⋅62x(x+2)=[ (x−2)(x+2)+1⋅2x ]2x(x+2)⋅2x(x+2)[ 3x(x+2)−2⋅6 ]=(x−2)(x+2)+1⋅2x3x(x+2)−2⋅6=(x−2)(x+2)+2x3x(x+2)−12=x2−4+2x3x2+6x−12=13⋅(x2+2x−4)(x2+2x−4)=13