${x}^{2} + 2x = 8$

Hello Guest,

Can anyone use the p-q formula to solve this equation?

\(x^2+2x=8\)

Thanks in advance

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the p-q formula: \(x_1 \mbox { and } x _2 = -\frac{p}{2} \pm \sqrt{\Big(\frac{p}{2}\Big)^2-q}\) .

\(x^2 + 2x = 8 \ |\ -8\)

. . . let \((p, \mbox { } q) = (2, \mbox { } -8)\) .

\(x_1 \mbox { and } x_2 = \frac{-2}{2} \pm \mbox {} \sqrt{\Big(\frac{2}{2}\Big)^2-(-8)}\)

\(x_1 \mbox { and } x_2 = -1 \pm \mbox {} \sqrt{ 1 + 8 }\)

\(x_1 = -1 + 3\)

\(x _1 = 2\)

\(x_2 = -1 - 3\)

\(x_2 = -4\)

This equation has two solutions, namely \(x_1 = 2\) and \(x_2 = -4\) .

Hope this was helpful. ^^

 !