(x 2 +3x-4)/(3x-7) Can u simplify and cancel the 3x in the denominator and numerator out

No you can't cancel the 3x's out!

(x²+3x-4)/(3x-7) can be written as (x+4)(x-1)/(3x-7)

Thanks, Alan....

BTW....here's a tip if you get stuck like this...it isn't necessarily foolproof, but it might give you a clue.....subsitute a non-zero integer for x and see if we have equivalent expressions if we " cancel" 3x out......I'll use x = 1

So

[x^2 + 3x - 4]  / [ 3x - 7]    evaluates  to    [0] / [-4]   = 0

But

[x^2 -4] /  [-7]     evaluates to [-3] / [-7]   = 3/7

So....."cancelling" 3x   does NOT result in an equivalent expression........!!!!