(x-2)^{x-3}<(x-2)^{5-x} what is the x?

I am going to try and do it by hand

$$\\(x-2)^{x-3}<(x-2)^{5-x}\\\\ (x-3)log(x-2)<(5-x)log(x-2)\\\\ (x-3)log(x-2)-(5-x)log(x-2)<0\\\\ (x-3-5+x)log(x-2)<0\\\\ (2x-8)log(x-2)<0\\\\ (x-4)log(x-2)<0$$

this will be true if one of the factors is negative and the other is positive.

log(x-2)>0 when x-2>1    that is when x>3

x-4>0                                    when   x>4  

so

If x4 then both are negative.

BUT   the goldilocks moment comes

when  x is between 3 and 4 because then x-4 is neg and log(x-2) is positive

so

This will be true when     3<x<4

Plotting a graph often helps:

.

Thanks Alan,

So you want the blue graph to be UNDER the green graph (because it is less than)

this appears to happen between x=3 and x=4  :))

3<x<4