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# x^3/x^-2 ?

0
451
5

this might seem simple , but what is x^3/x^-2 ?

_fio

Nov 12, 2014

#2
+8

A  variable with  negative exponent in a fraction can always "travel" across the fraction bar. It's exponent then becomes positive......

So we have

x^3 / x^ -2 =

(x^3) * (x^2) =

x^5   Nov 12, 2014

#1
0

I know math but I'm only average. According to my head:

I think you can't answer that....

$${\frac{{{\mathtt{x}}}^{{\mathtt{3}}}}{{{\mathtt{x}}}^{-{\mathtt{2}}}}} = {\frac{{{\left(\underset{{\tiny{\text{Error: Unknown Identifier}}}}{{\mathtt{x}}}\right)}}^{{\mathtt{3}}}}{{{\left(\underset{{\tiny{\text{Error: Unknown Identifier}}}}{{\mathtt{x}}}\right)}}^{-{\mathtt{2}}}}}$$

or

$${\frac{{\frac{{{\mathtt{x}}}^{{\mathtt{3}}}}{{\mathtt{1}}}}}{{\mathtt{x}}}} = {\frac{{\frac{{{\left(\underset{{\tiny{\text{Error: Unknown Identifier}}}}{{\mathtt{x}}}\right)}}^{{\mathtt{3}}}}{{\mathtt{1}}}}}{\underset{{\tiny{\text{Error: Unknown Identifier}}}}{{\mathtt{x}}}}}$$

Therefore, you cannot answer that without any given values..

Nov 12, 2014
#2
+8

A  variable with  negative exponent in a fraction can always "travel" across the fraction bar. It's exponent then becomes positive......

So we have

x^3 / x^ -2 =

(x^3) * (x^2) =

x^5   CPhill Nov 12, 2014
#3
0

CPhill I thought that if you get a negative exponent then you will have to get the reciprocal?

Nov 12, 2014
#4
+5

We would have a reciprocal....   Note...

x^3 / x^-2  =

(x^3 / 1) / ( x^-2) =

(x^3 / 1) / (1/ x^2) =

(x ^ 3 / 1) * (x^2 / 1) =

x^5

Does that make sense ??   Nov 12, 2014
#5
0

Ohh... lol

Nov 12, 2014