I know math but I'm only average. According to my head:
I think you can't answer that....
$${\frac{{{\mathtt{x}}}^{{\mathtt{3}}}}{{{\mathtt{x}}}^{-{\mathtt{2}}}}} = {\frac{{{\left(\underset{{\tiny{\text{Error: Unknown Identifier}}}}{{\mathtt{x}}}\right)}}^{{\mathtt{3}}}}{{{\left(\underset{{\tiny{\text{Error: Unknown Identifier}}}}{{\mathtt{x}}}\right)}}^{-{\mathtt{2}}}}}$$
or
$${\frac{{\frac{{{\mathtt{x}}}^{{\mathtt{3}}}}{{\mathtt{1}}}}}{{\mathtt{x}}}} = {\frac{{\frac{{{\left(\underset{{\tiny{\text{Error: Unknown Identifier}}}}{{\mathtt{x}}}\right)}}^{{\mathtt{3}}}}{{\mathtt{1}}}}}{\underset{{\tiny{\text{Error: Unknown Identifier}}}}{{\mathtt{x}}}}}$$
Therefore, you cannot answer that without any given values..
A variable with negative exponent in a fraction can always "travel" across the fraction bar. It's exponent then becomes positive......
So we have
x^3 / x^ -2 =
(x^3) * (x^2) =
x^5
CPhill I thought that if you get a negative exponent then you will have to get the reciprocal?