We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
522
3
avatar

x^3+x^2+2x+2 factor by grouping so it ends up with two binomials.

 Dec 5, 2014

Best Answer 

 #2
avatar+22150 
+5

x^3+x^2+2x+2 factor by grouping so it ends up with two binomials.

$$\small{
\text{Formula:}
$
\boxed{a+ax+x^2+x^3 = (1+x)(a+x^2)}
\\\\
$
\text{Example: }
$\\$
a=2 \qquad 2+2x+x^2+x^3 = (1+x)(2+x^2) \\
a=1 \qquad 1+1x+x^2+x^3 = (1+x)(1+x^2)
$
}$$

.
 Dec 5, 2014
 #1
avatar
+5

You have to play around with it a bit (or a lot) using trial-and-error trying different possibilities until it works.

 

Check your answer here: http://m.wolframalpha.com/input/?i=factorize+x%5E3%2Bx%5E2%2B2x%2B2&x=0&y=0

 

 Dec 5, 2014
 #2
avatar+22150 
+5
Best Answer

x^3+x^2+2x+2 factor by grouping so it ends up with two binomials.

$$\small{
\text{Formula:}
$
\boxed{a+ax+x^2+x^3 = (1+x)(a+x^2)}
\\\\
$
\text{Example: }
$\\$
a=2 \qquad 2+2x+x^2+x^3 = (1+x)(2+x^2) \\
a=1 \qquad 1+1x+x^2+x^3 = (1+x)(1+x^2)
$
}$$

heureka Dec 5, 2014
 #3
avatar+100778 
0

This factorization could be handy to remember.  Thanks Heureka.

 Dec 5, 2014

13 Online Users

avatar