12×(x6−51)+5×(x5+41)+10=6×(x1−351)
through calculater the answer is 60 yet no way of solution please help
I see you've answered Alan, but I had to post this because I put like 10 minutes into this LaTeX. :)
12(x6−51)+5(x5+41)+10=6(x1−351)Distribute the 12, 5, and 6 into their parentheses(12×x6)−(12×51)+(5×x5)+(5×41)+10=(6×x1)−(6×351)(12x6)−(601)+(5x5)+(201)+10=6x1−2101(2x1)−(601)+(x1)+(201)+10=6x1−21012x−60+x+20+10=6x−2103x−60+20+10=6x−2103x−30=6x−210−30=3x−210180=3x60=xx=60
Multiplying through to get rid of the brackets this becomes:
2x - 60 + x + 20 + 10 = 6x - 210
or: 3x - 30 = 6x - 210
Add 210 to both sides:
3x + 180 = 6x
Subtract 3x from both sides:
180 = 3x
Divide both sides by 3:
x = 60
I see you've answered Alan, but I had to post this because I put like 10 minutes into this LaTeX. :)
12(x6−51)+5(x5+41)+10=6(x1−351)Distribute the 12, 5, and 6 into their parentheses(12×x6)−(12×51)+(5×x5)+(5×41)+10=(6×x1)−(6×351)(12x6)−(601)+(5x5)+(201)+10=6x1−2101(2x1)−(601)+(x1)+(201)+10=6x1−21012x−60+x+20+10=6x−2103x−60+20+10=6x−2103x−30=6x−210−30=3x−210180=3x60=xx=60