Hi,
I'm trying to find the x-intercepts of the function: y = x2 - 6x - 9
Thanks for the help!
Lily
The x intercepts occur where y = 0 ....so....
x^2 - 6x - 9 = 0 complete the square.....add 9 to both sides
x^2 - 6x = 9 take 1/2 of 6 = 3......square this and add to both sides
x^2 - 6x + 9 = 9 + 9
x^2 - 6x + 9 = 18 factor the left side
(x - 3)^2 = 18 take the square root of both sides
x - 3 = pos/neg sqrt(18) = pos/neg 3sqrt(2)
x - 3 = pos/neg 3sqrt(2) add 3 to both sides
x = pos/neg 3sqrt(2) + 3
So x = 3sqrt(2) +3 and x = -3sqrt(2) + 3