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when I solved a polynomial i got this

(x-3)(x^2+5)=0

so x=3 or x=+-sqrt(-5) are the x intercepts and since the sqrt of -5 is 5i does that mean there is only one x intercept?

Guest Apr 8, 2017
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 #1
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Yep.....this only has one real root [ one x intercept]  at x  = 3

 

The other factor , x^2 + 5    has  two non-real solutions

 

Since this is a 3rd power polynomial, we will have either three real roots or one real root and two non-real roots, as in this situation.

 

 

 

cool cool cool

CPhill  Apr 8, 2017
 #2
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+1

TY

 

I was doing practice problems at ramdoms so this helps get rid of some of my mis conseptions.

Guest Apr 8, 2017

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