when I solved a polynomial i got this

(x-3)(x^2+5)=0

so x=3 or x=+-sqrt(-5) are the x intercepts and since the sqrt of -5 is 5i does that mean there is only one x intercept?

Yep.....this only has one real root [ one x intercept] at x = 3

The other factor , x^2 + 5 has two non-real solutions

Since this is a 3rd power polynomial, we will have either three real roots or one real root and two non-real roots, as in this situation.

TY

I was doing practice problems at ramdoms so this helps get rid of some of my mis conseptions.