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x √(x+(√x-2)=2

can you please show me how to solve for x?

 

thanks!

 Jan 21, 2016

Best Answer 

 #1
avatar+129847 
+10

I believe this is supposed to  be  x √(x+(√x-2))=2

 

x √(x+(√x-2))= 2   divide both sides by x

 

√(x+(√x-2))  = 2/x  squre both sides

 

x + √x  - 2  =  4/x^2

 

√x  = 4/x^2  - x  + 2   

 

√x  = [ 4 - x^3  + 2x^2] / x^2      multiply both sides by x^2

 

x^(5/2)  = 4 - x^3 + 2x^2

 

x^3 + x^(5/2) -2x^2 - 4  = 0     

 

WolframAlpha shows the solution to this as   x ≈ 1.83436

 

 

cool cool cool

 Jan 21, 2016
 #1
avatar+129847 
+10
Best Answer

I believe this is supposed to  be  x √(x+(√x-2))=2

 

x √(x+(√x-2))= 2   divide both sides by x

 

√(x+(√x-2))  = 2/x  squre both sides

 

x + √x  - 2  =  4/x^2

 

√x  = 4/x^2  - x  + 2   

 

√x  = [ 4 - x^3  + 2x^2] / x^2      multiply both sides by x^2

 

x^(5/2)  = 4 - x^3 + 2x^2

 

x^3 + x^(5/2) -2x^2 - 4  = 0     

 

WolframAlpha shows the solution to this as   x ≈ 1.83436

 

 

cool cool cool

CPhill Jan 21, 2016

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