Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
0
654
1
avatar

If x,y , and z are positive real numbers satisfying:

log(x/y) = a

log(y/z)  = 15

log(z/x) = -1

 

Find a.

 Oct 19, 2020
 #1
avatar+15077 
+1

If x,y , and z are positive real numbers satisfying:

log(x/y) = a

log(y/z)  = 15

log(z/x) = -1

 

Hello Guest!

 

log(xy)=alog(yz)=15log(zx)=1

log(x)log(y)=alog(y)log(z)=15log(z)log(x)=1

XY=aYZ=15ZX=1     

Z=X1

Y=Xa=15Za=X+Z15a=X+X115a=2X16

a=log(x2)16

laugh  !

 Oct 19, 2020

3 Online Users

avatar
avatar