+0  
 
+5
255
1
avatar

y=_x+_ with the points of (3,-2) and(6,4) using point slope form

Guest Jul 13, 2015

Best Answer 

 #1
avatar+17711 
+5

The point-slope form is:  y - y1 = m(x - x1)

where the point is (x1, y1) and the slope is m.  m  =  (y2 - y1) / (x2 - x1)

For this problem:  x1 = 3, y1 = -2, x2 = 6, and y2 = 4.

Therefore:  m  =  (4 - -2) / (6 - 3)  =  6/3  =  2

The equation is:  y - -2  =  2(x - 3)     --->     y + 2  =  2x - 6     --->     y  = 2x - 8

geno3141  Jul 13, 2015
Sort: 

1+0 Answers

 #1
avatar+17711 
+5
Best Answer

The point-slope form is:  y - y1 = m(x - x1)

where the point is (x1, y1) and the slope is m.  m  =  (y2 - y1) / (x2 - x1)

For this problem:  x1 = 3, y1 = -2, x2 = 6, and y2 = 4.

Therefore:  m  =  (4 - -2) / (6 - 3)  =  6/3  =  2

The equation is:  y - -2  =  2(x - 3)     --->     y + 2  =  2x - 6     --->     y  = 2x - 8

geno3141  Jul 13, 2015

22 Online Users

avatar
avatar
avatar
avatar
avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details