y=_x+_ with the points of (3,-2) and(6,4) using point slope form

The point-slope form is:  y - y₁ = m(x - x₁)

where the point is (x₁, y₁) and the slope is m.  m  =  (y₂ - y₁) / (x₂ - x₁)

For this problem:  x₁ = 3, y₁ = -2, x₂ = 6, and y₂ = 4.

Therefore:  m  =  (4 - -2) / (6 - 3)  =  6/3  =  2

The equation is:  y - -2  =  2(x - 3)     --->     y + 2  =  2x - 6     --->     y  = 2x - 8