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Let

f(x) = 2x^2 - 3 if x >= 2

         ax + 7 if x > 2

Find a if the graph of y = f(x) is continuous (which means the graph can be drawn without lifting your pencil from the paper).

 Oct 27, 2020
 #1
avatar+14995 
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Let

f(x) = 2x^2 - 3 if x >= 2

         ax + 7 if x > 2

Find a if the graph of y = f(x) is continuous

 

Hello Guest!

 

f(x) = 2x^2 - 3

\(f(x) = 2x^2 - 3=ax+7\\ x=2\\ 2\cdot 2^2-3=2a+7\\ a=(8-3-7)/2\)

\(a=-1\)

laugh  !

 Oct 27, 2020

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