Let
f(x) = 2x^2 - 3 if x >= 2
ax + 7 if x > 2
Find a if the graph of y = f(x) is continuous (which means the graph can be drawn without lifting your pencil from the paper).
Find a if the graph of y = f(x) is continuous
Hello Guest!
f(x) = 2x^2 - 3
\(f(x) = 2x^2 - 3=ax+7\\ x=2\\ 2\cdot 2^2-3=2a+7\\ a=(8-3-7)/2\)
\(a=-1\)
!