+0

# y-intercept form to standard form

0
603
1
+415

how do I turn this y= 29.95x+99

Into standard form?

I got

0=29.95x-y-99

but i think it's wrong

Jan 25, 2017

#1
+24932
+60

Converting from slope-intercept to standard form

how do I turn this y= 29.95x+99

$$\begin{array}{|c|c|} \hline \text{Slope-intercept form } y = mx+b & \text{Standard form } Ax+By = C \\ \hline \begin{array}{rcll} y &=& 29.95x+99 \qquad &| -29.95x \\ -29.95x + y &=& 99 \qquad &| \cdot 20 \\ -599x + 20y &=& 1980\\ \end{array} & \begin{array}{rcll} \\ \\ -599x + 20y &=& 1980\\ \end{array} \\ \hline \end{array}$$

Jan 25, 2017

#1
+24932
+60

Converting from slope-intercept to standard form

how do I turn this y= 29.95x+99

$$\begin{array}{|c|c|} \hline \text{Slope-intercept form } y = mx+b & \text{Standard form } Ax+By = C \\ \hline \begin{array}{rcll} y &=& 29.95x+99 \qquad &| -29.95x \\ -29.95x + y &=& 99 \qquad &| \cdot 20 \\ -599x + 20y &=& 1980\\ \end{array} & \begin{array}{rcll} \\ \\ -599x + 20y &=& 1980\\ \end{array} \\ \hline \end{array}$$

heureka Jan 25, 2017