+448 how do I turn this y= 29.95x+99
Into standard form?
I got
0=29.95x-y-99
but i think it's wrong
+26367 Converting from slope-intercept to standard form
how do I turn this y= 29.95x+99
\(\begin{array}{|c|c|} \hline \text{Slope-intercept form } y = mx+b & \text{Standard form } Ax+By = C \\ \hline \begin{array}{rcll} y &=& 29.95x+99 \qquad &| -29.95x \\ -29.95x + y &=& 99 \qquad &| \cdot 20 \\ -599x + 20y &=& 1980\\ \end{array} & \begin{array}{rcll} \\ \\ -599x + 20y &=& 1980\\ \end{array} \\ \hline \end{array}\)
+26367 Converting from slope-intercept to standard form
how do I turn this y= 29.95x+99
\(\begin{array}{|c|c|} \hline \text{Slope-intercept form } y = mx+b & \text{Standard form } Ax+By = C \\ \hline \begin{array}{rcll} y &=& 29.95x+99 \qquad &| -29.95x \\ -29.95x + y &=& 99 \qquad &| \cdot 20 \\ -599x + 20y &=& 1980\\ \end{array} & \begin{array}{rcll} \\ \\ -599x + 20y &=& 1980\\ \end{array} \\ \hline \end{array}\)
