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# You drop a penny from a height of 16 feet. After how many seconds does the penny land on the ground? Formula: h = -16t^2 + vt + s

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In Algebra, you drop a penny from a height of 16 feet. After how many seconds does the penny land on the ground? Formula: h = -16t^2 + vt + s

Mar 7, 2018

### Best Answer

#1
+18458
+2

Assuming no friction or terminal velocity:

h = 0 when it hits the ground     find t

0 = 16t^2+vt + s       v = 0  as you drop it     and s= 16 at the starting point

0= -16t^2 + 16

-16 = - 16t^2

1= t^2                t=1 sec

Mar 7, 2018
edited by ElectricPavlov  Mar 7, 2018

### 2+0 Answers

#1
+18458
+2
Best Answer

Assuming no friction or terminal velocity:

h = 0 when it hits the ground     find t

0 = 16t^2+vt + s       v = 0  as you drop it     and s= 16 at the starting point

0= -16t^2 + 16

-16 = - 16t^2

1= t^2                t=1 sec

ElectricPavlov Mar 7, 2018
edited by ElectricPavlov  Mar 7, 2018
#2
-18
-3

Thanks so much! This question got me stuck.

GAMEMASTERX40  Mar 7, 2018