+0  
 
+8
746
4
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You know (6! - 3!) - ((6 × 100) - ((6 ÷ 3) × 100))) / 100 = 3.14!

 Sep 15, 2014

Best Answer 

 #3
avatar+129840 
+8

DS...those "exclamation marks" are called "factorials"....in simple terms, n!  = the product of the first "n" positive integers......for example:

3!  = the product of the first three positive integers = 3x 2 x 1  = 6

4! = the product of the first four positive integeers = 4 x 3 x 2 x 1  = 24

......etc......

This is a very important idea in statistics and probability. It's used to "count" things.... (sets, arrangements of objects, etc.)

Hope that helps  !!!

 

 Sep 15, 2014
 #1
avatar+118654 
+8

$$\left({\mathtt{6}}{!}{\mathtt{\,-\,}}{\mathtt{3}}{!}\right) = {\mathtt{714}}$$

((6! - 3!) - ((6 × 100) - ((6 ÷ 3) × 100))) / 100

(714 - (600 - (2 × 100))) / 100

 

(714 - (600 - 200)) / 100

(714 - 400) / 100

Except for the missing bracket, you are correct!    

 Sep 15, 2014
 #2
avatar+8262 
0

What are the exclamation marks used for???

 Sep 15, 2014
 #3
avatar+129840 
+8
Best Answer

DS...those "exclamation marks" are called "factorials"....in simple terms, n!  = the product of the first "n" positive integers......for example:

3!  = the product of the first three positive integers = 3x 2 x 1  = 6

4! = the product of the first four positive integeers = 4 x 3 x 2 x 1  = 24

......etc......

This is a very important idea in statistics and probability. It's used to "count" things.... (sets, arrangements of objects, etc.)

Hope that helps  !!!

 

CPhill Sep 15, 2014
 #4
avatar+8262 
0

Thanks! Later on, I will post something about factorials

 Sep 15, 2014

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