In a normally distributed set of scores, the mean is 74 and the standard deviation is 1.5. What is the probability that a randomly selected score is between 72.5 and 77? Answer should be written as a percent. Do not round.

ONE standard deviation below 74 is 74 - 1.5 = 72.5 z -score = .1587

77 is two standard deviations ABOVE 74 z-score = .9772

we want to now the area between these z-scores

.9772 - .1587 = .8185 so 81.85% out of 100% of the scores are between 72.5 and 77