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What is the perimeter of the polygon formed when the points A(-6,6) B(9,6) and C(9,-2) are graphed and connected with straight lines?

 Apr 30, 2020
 #1
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AB  = sqrt  [ (-6 - 9)^2  + (6 - 6)^2) ]  =  sqrt  [ 15^2]  =  15

 

BC  =  sqrt  [ ((9- 9)^2  + ( -2 - 6)^2 ]  =   sqrt [ 64]  =  8

 

AC  =  sqrt [ (-6 - 9)^2  + (-2 - 6)^2) ] =  sqrt  [ 15^2  +8^2]  = sqrt [ 289]  =  17

 

Perimeter  =  15 + 8  +  17   =   40

 

 

 

cool cool cool

 Apr 30, 2020
 #2
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+1

Thank you!

Guest Apr 30, 2020

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