The lines \(y = \frac{1}{3} x\) and \(y = \frac{13}{9} x\) are drawn in the coordinate plane. Find the slope of the line that bisects the angle between these lines.
13/12
Are you sure?
Here's one way to do this
arctan (13/9) + arctan (1/3)
______________________ = theta
2
tan (theta) =
tan [ ( arctan (13/9) + arctan (1/3)) / 2 ] = 3/4 = the slope of the bisector
See the graph here : https://www.desmos.com/calculator/jssgzsmyoq
Thank you very much!
+166 
