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The lines \(y = \frac{1}{3} x\) and \(y = \frac{13}{9} x\) are drawn in the coordinate plane. Find the slope of the line that bisects the angle between these lines.

 Apr 30, 2020
 #1
avatar+116 
-1

13/12

 Apr 30, 2020
edited by grannygod123  Apr 30, 2020
 #2
avatar+172 
+1

Are you sure?

HannibalBarca  Apr 30, 2020
 #3
avatar+111329 
+2

Here's  one way to do this

 

arctan (13/9)  + arctan (1/3)

______________________     =  theta     

               2

 

tan (theta)  =

 

tan  [  ( arctan (13/9)  + arctan (1/3))  / 2 ]   =    3/4   = the slope of the  bisector

 

See the graph here  : https://www.desmos.com/calculator/jssgzsmyoq

 

 

cool cool cool

 Apr 30, 2020
 #4
avatar+172 
+2

Thank you very much! laugh

HannibalBarca  Apr 30, 2020

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