The series will be arithmetic
Since the average of the 26th and 28th terms = 94 and the average of the 93rd and 95th terms = 46, we can write :
2a27 = a26 + a28 2a94 = a93 + a95
188 = a26 + a28 92 = a93 + a95
And we have that
a27 = a1 + d ( 26) (1)
a94 = a1 + d (93) (2)
Multiply (1) and (2) through by 2
2a27 = 2a1 + 2d (26)
2a94 = 2a1 + 2d( 93)
188 = 2a1 + 52d (3)
92 = 2a1 + 186d (4)
Subtract ( 4) from (3) and solve for d
96 = -134d
d = 96/-134 = -48/67
Using (1) and subbing to solve for a1
94 = a1 - 48/67 ( 26)
94 + 48/67 (26) = a1
7546 / 67 = a1
