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John and Jack divided their math homework. John solved twice as many problems as Jack, plus one more problem. How many problems did each boy solve if there are 28 assigned problems?

 May 21, 2021
 #1
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Let  the  number  that  Jack  solved  =  N

Then John solved  2N +  1

 

So

 

N  + 2N +  1  =   28

 

3N   =  28  -  1

 

3N  =   27

 

N =  27  / 3    =  9   =   number Jack solved

 

2(9) + 1   =  19  =  number John solved

 

cool cool cool

 May 21, 2021

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